README.md

2169. Count Operations to Obtain Zero

You are given two non-negative integers num1 and num2.

In one operation, if num1 >= num2, you must subtract num2 from num1, otherwise subtract num1 from num2.

• For example, if num1 = 5 and num2 = 4, subtract num2 from num1, thus obtaining num1 = 1 and num2 = 4. However, if num1 = 4 and num2 = 5, after one operation, num1 = 4 and num2 = 1.

Return the number of operations required to make eithernum1 = 0ornum2 = 0.

Example 1:

Input: num1 = 2, num2 = 3 Output: 3 Explanation: - Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1. - Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1. - Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1. Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations. So the total number of operations required is 3. 

Example 2:

Input: num1 = 10, num2 = 10 Output: 1 Explanation: - Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0. Now num1 = 0 and num2 = 10. Since num1 == 0, we are done. So the total number of operations required is 1. 

Constraints:

• 0 <= num1, num2 <= 105

Solutions (Python)

1. Solution

classSolution: defcountOperations(self, num1: int, num2: int) ->int: ret=0whilenum1!=0andnum2!=0: ifnum1>=num2: num1-=num2else: num2-=num1ret+=1returnret